Mr. Rodriguez has a vegetable garden that borders his house. He wants to put a fence around it. It costs $7 per yard For the materials. Evaluate 7(l + 2w) where I is the length and w is the width of his garden, to find the cost for a garden that has a length of 5 yards and a width of 2 yards. (1 point)
To find the cost of the fence for a garden with a length of 5 yards and a width of 2 yards, we can substitute l = 5 and w = 2 into the expression 7(l + 2w).
7(l + 2w) = 7(5 + 2(2))
= 7(5 + 4)
= 7(9)
= 63.
Therefore, the cost for a garden with a length of 5 yards and a width of 2 yards is $63. Answer: \boxed{63}.
To find the cost for a garden with a length of 5 yards and a width of 2 yards, we can plug in the values into the equation 7(l + 2w) where l is the length and w is the width.
Given that the length (l) is 5 yards and the width (w) is 2 yards, we can substitute these values into the equation:
7(5 + 2(2))
Simplifying the equation:
7(5 + 4)
7(9)
63
Therefore, the cost for a garden with a length of 5 yards and a width of 2 yards is $63.
To find the cost for Mr. Rodriguez's garden, we need to calculate the perimeter of the garden and then multiply it by the cost per yard of materials.
The formula for the perimeter of a rectangle is given by P = 2(l + w), where l is the length and w is the width. However, in this case, we are given the formula 7(l + 2w), which suggests that the fence may have a different cost per yard for the width compared to the length.
Let's substitute the given values into the formula: l = 5 yards and w = 2 yards:
Cost = 7(l + 2w)
= 7(5 + 2(2))
= 7(5 + 4)
= 7(9)
= 63
Therefore, the cost for a garden with a length of 5 yards and a width of 2 yards would be $63.