Given the following nuclear reaction:

252/99es>0/-1e+a/zx

Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
a.Es
b.Md
c.Alpha Decay
d.100
e.251
f.248
g.253
h.Beta Decay
i.Gamma Decay
j.Fm
k.99
l.101
m.252

Column A:

1. What is the atomic mass of the new atom?: f. 248
2. What is the atomic number of the new atom?: m. 252
3. What is the symbol of the new atom?: b. Md
4. What type of decay is demonstrated here?: c. Alpha Decay

Column B:
a. Es
b. Md
c. Alpha Decay
d. 100
e. 251
f. 248
g. 253
h. Beta Decay
i. Gamma Decay
j. Fm
k. 99
l. 101
m. 252

Column A:

1. The atomic mass of the new atom is 252.
2. The atomic number of the new atom is 99.
3. The symbol of the new atom is Es.
4. The type of decay demonstrated here is Alpha Decay.

Column B:
a. Es (Symbol of the new atom)
b. Md
c. Alpha Decay (Type of decay demonstrated here)

To determine the answers to the questions in column A, we need to understand the given nuclear reaction:

252/99es > 0/-1e + a/zx

The reactant in the reaction is 252/99es, which represents an isotope of Einsteinium with an atomic number of 99 and atomic mass of 252. In the reaction, it undergoes decay, producing a new atom.

Now, let's answer each question in column A:

1. What is the atomic mass of the new atom?
The atomic mass of the new atom can be found by summing the atomic masses of the particles on the right side of the reaction. In this case, we have an electron (0/-1e) and an alpha particle (a/zx), which consists of two protons and two neutrons. By adding the atomic masses, we find that the atomic mass of the new atom is 248.

2. What is the atomic number of the new atom?
The atomic number of an atom is determined by the number of protons it contains. In this reaction, the alpha particle (a/zx) is released, which consists of two protons. Therefore, the atomic number of the new atom is 2.

3. What is the symbol of the new atom?
The symbol of an atom is based on its atomic number and the symbol of the corresponding element. In this case, since the atomic number is 2, the symbol of the new atom is He, which represents the chemical element helium.

4. What type of decay is demonstrated here?
The type of decay demonstrated in this reaction can be determined by analyzing the particles involved. The reaction shows the emission of an alpha particle (a/zx), which consists of two protons and two neutrons. This type of decay is known as alpha decay.

Now, let's match the answers from column A with the corresponding options in column B:

1. Answer: f. 248
The atomic mass of the new atom is 248.

2. Answer: d. 2
The atomic number of the new atom is 2.

3. Answer: b. Md
The symbol of the new atom is Md.

4. Answer: c. Alpha Decay
The type of decay demonstrated here is alpha decay.