Given the following nuclear reaction:
251/98cf>0/0y+a/zx
Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the atomic symbol of the new atom?:
What is the atomic symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
a.99
b.98
c.Bk
d.Cf
e.Beta Decay
Column A:
1. The atomic mass of the new atom is 251.
2. The atomic number of the new atom is 98.
3. The atomic symbol of the new atom is Cf (Californium).
4. The type of decay demonstrated here is Beta Decay.
Column B:
a. 99
b. 98
c. Bk
d. Cf
e. Beta Decay
To answer the questions in Column A, we need to understand the given nuclear reaction and determine the resulting atom.
In the given reaction:
251/98cf > 0/0y + a/zx
The reactant atom is a Cf (Californium) atom with an atomic mass of 251 and an atomic number of 98. The arrow (>) represents a nuclear reaction, and the products of the reaction are a Y (yttrium) atom with an atomic mass of 0 and an atomic number of 0, and an unknown atom represented by a symbol "x" with an atomic mass of "a" and an atomic number of "z."
Now let's answer the questions in Column A:
1. What is the atomic mass of the new atom?
The atomic mass of the new atom is represented by "a" in the reaction. However, the exact value of "a" is not given in the question. We cannot determine the atomic mass without this information.
2. What is the atomic number of the new atom?
The atomic number of the new atom is represented by "z" in the reaction. Similar to the previous question, the exact value of "z" is not provided, so we cannot determine the atomic number without this information.
3. What is the atomic symbol of the new atom?
The atomic symbol of the new atom is not explicitly given in the reaction. It is represented by the symbol "x" in the reaction. Without additional information about the new atom, we cannot determine its atomic symbol.
4. What type of decay is demonstrated here?
The type of decay demonstrated in the given reaction is beta decay. In beta decay, an unstable nucleus emits a beta particle (represented by "0/0y" in the reaction). The new atom formed after beta decay will have a different atomic number due to the emission of a beta particle.
Therefore, the answer to question 4 in Column A is "e. Beta Decay."
In summary, without further information about the resulting atom, we cannot determine its atomic mass, atomic number, or atomic symbol (questions 1, 2, and 3 in Column A). However, we can identify the type of decay as beta decay (question 4 in Column A).
1. The atomic mass of the new atom is the sum of the atomic masses of the products. In this case, the new atom is 0/0y, which has an atomic mass of 0.
2. The atomic number of the new atom is the same as the atomic number of the alpha particle (a/zx) produced. In this case, the alpha particle has an atomic number of 2.
3. The atomic symbol of the new atom is determined by combining the atomic symbol of the alpha particle with the atomic symbol of the isotope undergoing decay. In this case, the alpha particle has the atomic symbol "a" and the isotope undergoing decay is Cf (californium), so the new atom's atomic symbol is "aCf".
4. The type of decay demonstrated here is beta decay. Beta decay occurs when a neutron in the nucleus transforms into a proton, emitting a beta particle (in this case, the product 0/0y), which is an electron or a positron.