Students can choose French or Spanish as an elective. There are 4 times as many seats for French than there is Spanish. How many students can choose Spanish if there is 250 students?
Let x be the number of students who can choose Spanish.
The number of seats for French is 4x.
The total number of seats for both elective subjects is x + 4x = 250 students.
Combining like terms, we get 5x = 250 students.
Dividing both sides by 5, we get x = <<50=50>>50 students. Answer: \boxed{50}.
To find out how many students can choose Spanish, we need to determine the ratio of seats for French to seats for Spanish.
It is given that there are 4 times as many seats for French, which means for every seat for Spanish, there are 4 seats for French.
Let's assume the number of seats for Spanish is x. Then, the number of seats for French would be 4x.
The total number of seats available for both French and Spanish is given as 250. So, we can set up the equation:
x + 4x = 250
Combining like terms:
5x = 250
To isolate x, we divide both sides of the equation by 5:
5x/5 = 250/5
x = 50
Therefore, there are 50 seats for Spanish, which means 50 students can choose Spanish as an elective.
To find out how many students can choose Spanish, we need to determine the ratio of seats available for French to Spanish.
Let's assume the number of seats for Spanish is "x". According to the information given, there are 4 times as many seats for French as there are for Spanish. So the number of seats for French would be 4x.
The total number of students is 250, and we know that the number of students who can choose Spanish plus the number of students who can choose French should be equal to the total number of students.
Therefore, we can set up the following equation:
x + 4x = 250
Combining like terms, we have:
5x = 250
To isolate x, we divide both sides of the equation by 5:
5x/5 = 250/5
x = 50
So, there are 50 seats available for Spanish. Hence, 50 students can choose Spanish as an elective.