Joseph wants to buy tickets for the baseball game and a team hat to wear to the game. He has $34.25 if the hat cost $12 and 50 Cent and tickets cost $7.25 each. How many tickets can he buy
The total cost of the hat and tickets is $12 + $7.25 + $7.25 = $<<12+7.25+7.25=26.5>>26.5
Joseph has $34.25 - $26.5 = $<<34.25-26.5=7.75>>7.75 left
Joseph can buy 7.75 / $7.25 = 1 ticket
Joseph can buy 1 ticket. Answer: \boxed{1}.
To determine how many baseball game tickets Joseph can buy, we need to subtract the cost of the hat from the total amount of money he has, and then divide that by the cost of each ticket.
Step 1: Determine the amount of money Joseph has left after buying the hat.
Joseph has $34.25 and the hat costs $12.50, so we subtract $12.50 from $34.25:
$34.25 - $12.50 = $21.75
Step 2: Calculate the number of tickets Joseph can buy.
Each ticket costs $7.25, so we divide the remaining money by the cost of each ticket:
$21.75 ÷ $7.25 = 3
Therefore, Joseph can buy 3 tickets for the baseball game.
To find out how many tickets Joseph can buy, we need to subtract the cost of the hat from his total budget, and then divide the remaining amount by the cost of each ticket.
1. Start with Joseph's budget: $34.25
2. Subtract the cost of the hat: $34.25 - $12.50 = $21.75
3. Divide the remaining amount by the cost of each ticket: $21.75 ÷ $7.25 = 3
Joseph can buy 3 tickets to the baseball game.