Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope?(1 point)
Responses
The forces are in the same direction, so the newtons can be added.
The forces are in the same direction, so the newtons can be added.
The forces are in opposite directions, so the newtons can be subtracted.
The forces are in opposite directions, so the newtons can be subtracted.
The forces are in opposite directions, so the newtons can be divided.
The forces are in opposite directions, so the newtons can be divided.
The newtons are in the same direction, so the newtons can be multiplied.
The forces are in opposite directions, so the newtons can be subtracted.
To determine the net force on the rope, we need to consider the forces acting in opposite directions. In this case, five children are pulling with a force of 10 newtons in one direction, and ten children are pulling with a force of 15 newtons in the opposite direction.
To find the net force, we subtract the force acting in the opposite direction. So, we subtract 15 newtons (the force of the ten children) from 10 newtons (the force of the five children).
Net force = 10 newtons - 15 newtons = -5 newtons
Therefore, the net force on the rope is -5 newtons, indicating that the force pulling in one direction is greater than the force pulling in the opposite direction.