A shortstop is standing in the base path between second and third base when she fields the ball. She is 25 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.%0D%0A%0D%0A(1 point)

Question

A shortstop is standing in the base path between second and third base when she fields the ball. She is 25 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.%0D%0A%0D%0A(1 point)

Answer 1

To find the distance the shortstop needs to throw the ball, we can use the Pythagorean theorem since the field is square.

Using the theorem, the distance she needs to throw the ball is given by the square root of the sum of the squares of the distances between the bases.

The distance between second base and first base is 90 feet (assuming we are on a regulation size baseball field).

Using the theorem, we calculate the distance she needs to throw the ball as follows:

Distance = √(25^2 + 90^2) = √(625 + 8100) = √8725 = 93.4 feet.

Therefore, she needs to throw the ball approximately 93.4 feet to first base.

Answer 2

To find the distance the shortstop needs to throw the ball, we first need to determine the distance from second base to first base.

Since the field is square, the distance from second base to first base will be the same as the distance from second base to third base.

Using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides, we can calculate the distance from second base to first base.

Let's call the distance from second base to first base "x", and the distance from second base to third base "25 feet".

Using the Pythagorean theorem, we can set up the equation:

x^2 = 25^2 + 25^2

Simplifying the equation:

x^2 = 625 + 625

x^2 = 1250

Taking the square root of both sides to solve for x:

x = √(1250)

x ≈ 35.36 feet

Therefore, the shortstop needs to throw the ball approximately 35.4 feet to first base.

Answer 3

To solve this problem, we need to use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the distance from the shortstop to second base represents the base path, and the distance from second base to first base represents the hypotenuse of a right triangle. The distance from the shortstop to second base (25 feet) represents one side of the triangle, and the distance from second base to first base represents the other side.

Let's call the distance from second base to first base "x". By using the Pythagorean theorem, we can write the equation:

x^2 = (25 feet)^2 + (x feet)^2

Simplifying the equation, we get:

x^2 = 625 feet^2 + x^2

Combining like terms, we have:

0 = 625 feet^2

We can clearly see that this equation does not have a solution, which means there is an error in the problem statement. Please verify the given information to find the accurate measurements.