When Clark was 7 years old he had 22 rare coins. Each year Clark added 15 coins to his collection. Assuming Clark does not sell or lose any coins, how old will Clark be when he has 577 coins?
Responses
A 3030
B 3131
C 3737
D 3838
E 44
To solve this problem, we can set up an equation using the given information.
Let x represent the number of years that have passed since Clark was 7 years old.
Since Clark started with 22 coins and added 15 coins each year, the equation would be:
22 + 15x = 577
To solve for x, we need to isolate it on one side of the equation. We can do this by subtracting 22 from both sides:
15x = 577 - 22
15x = 555
Now, divide both sides of the equation by 15:
x = 555/15
x = 37
Therefore, Clark will be 7 + 37 = 44 years old when he has 577 coins.
Answer: E) 44
To solve this problem, we need to find out how many years it takes for Clark to collect 577 coins.
Let's start by finding out how many coins Clark collects each year.
At 7 years old, Clark has 22 coins.
At 8 years old, he has 22 + 15 = <<22+15=37>>37 coins.
At 9 years old, he has 37 + 15 = <<37+15=52>>52 coins.
And so on.
We can see that Clark adds 15 coins to his collection each year. Therefore, the number of coins he has at a certain age is 22 + 15 * (age - 7). We can write this equation as:
22 + 15 * (age - 7) = 577.
Now, let's solve for age:
15 * (age - 7) = 577 - 22,
15 * (age - 7) = 555,
age - 7 = 37,
age = 37 + 7,
age = 44.
Therefore, Clark will be 44 years old when he has 577 coins.
The correct answer is E. 44.
To solve this problem, we can set up an equation to represent the relationship between Clark's age and the number of coins he has.
Let x represent Clark's age.
The number of coins Clark has can be represented by the equation:
22 + 15(x - 7) = 577
To find Clark's age when he has 577 coins, we need to solve this equation for x.
First, let's simplify the equation:
22 + 15x - 105 = 577
Next, combine the like terms:
15x - 83 = 577
Now, let's isolate the variable by moving the constant terms to the other side of the equation:
15x = 577 + 83
15x = 660
Finally, divide both sides of the equation by 15 to solve for x:
x = 660 / 15
x = 44
Therefore, Clark will be 44 years old when he has 577 coins.
So the answer is E: 44.