A 55 kg block of granite has an original temperature of 15.0°C. What will be the final temperature of this granite if 4.5 x 10 4kJ of heat energy are added to the granite? Use the specific heat of granite from question 9.
To find the final temperature of the granite, we need to use the formula:
q = mcΔT
where q is the heat energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
In this case, we are given that q = 4.5 x 10^4 kJ, m = 55 kg, and c is the specific heat of granite.
From question 9, let's say the specific heat of granite is x kJ/(kg°C).
Plugging in the given values, we have:
4.5 x 10^4 kJ = (55 kg) * x kJ/(kg°C) * ΔT
Now, we need to rearrange the formula to solve for ΔT:
ΔT = q / (m * c)
ΔT = (4.5 x 10^4 kJ) / (55 kg * x kJ/(kg°C))
Simplifying, the units kJ cancel out:
ΔT = (4.5 x 10^4) / (55 x)
To find the final temperature of the granite, we need to add the change in temperature ΔT to the original temperature of 15.0°C:
final temperature = 15.0°C + ΔT
So, the final temperature of the granite will be 15.0°C + (4.5 x 10^4) / (55 x)°C.
To find the final temperature of the granite, we need to use the equation:
q = mcΔT
where:
q = heat energy added (in joules)
m = mass of the granite (in kg)
c = specific heat of granite (in J/kg°C)
ΔT = change in temperature (in °C)
First, let's convert the heat energy from kilojoules to joules:
4.5 x 10^4 kJ = 4.5 x 10^4 x 10^3 J
= 4.5 x 10^7 J
Given:
m = 55 kg
c = specific heat of granite (from question 9)
Now, we can rearrange the equation to solve for ΔT:
ΔT = q / (mc)
ΔT = (4.5 x 10^7 J) / (55 kg * c)
We need the specific heat of granite (c) from question 9 to find the final temperature. Can you provide the specific heat value for granite?
To find the final temperature of the granite, we can use the equation:
q = mcΔT
Where:
q is the heat energy added to the granite
m is the mass of the granite
c is the specific heat of the granite
ΔT is the change in temperature
In this case, we are given the heat energy added to the granite (q) as 4.5 x 10^4 kJ. The mass of the granite (m) is given as 55 kg. We need to find the final temperature (ΔT).
First, we need to rearrange the equation to solve for ΔT:
ΔT = q / (mc)
Next, we need to substitute the given values into the equation:
ΔT = (4.5 x 10^4 kJ) / (55 kg * c)
However, we are also given that the specific heat of granite is given in question 9. Since we don't have the specific heat value, we cannot calculate the final temperature without that information. Please provide the specific heat of granite, and I will be able to complete the calculation.