Granite has a specific heat of 800. J/g∙°C. What mass of granite is needed to store 1.50 x 10 6J of heat if the temperature of the granite is to be increased by 15.5°C?
To calculate the mass of granite needed to store 1.50 x 10^6 J of heat, we can use the formula:
Q = mcΔT
Where:
Q is the heat energy (in J)
m is the mass (in g)
c is the specific heat (in J/g°C)
ΔT is the change in temperature (in °C)
Plugging in the given values:
1.50 x 10^6 J = m * 800 J/g°C * 15.5°C
Simplifying the equation:
1.50 x 10^6 J = m * 12400 J/g
Divide both sides of the equation by 12400 J/g:
m = (1.50 x 10^6 J) / (12400 J/g)
Calculating value:
m = 120.96875 g
Therefore, approximately 120.97 grams of granite is needed to store 1.50 x 10^6 J of heat when the temperature of the granite is increased by 15.5°C.
To calculate the mass of granite needed to store a specific amount of heat, we can use the formula:
q = m * c * ΔT
Where:
q = heat energy (Joules)
m = mass of granite (grams)
c = specific heat capacity of granite (J/g∙°C)
ΔT = change in temperature (°C)
Given:
q = 1.50 x 10^6 J
c = 800 J/g∙°C
ΔT = 15.5°C
We can rearrange the formula to solve for mass (m):
m = q / (c * ΔT)
Plugging in the values, we get:
m = (1.50 x 10^6 J) / (800 J/g∙°C * 15.5°C)
m ≈ 122.58 g
Therefore, approximately 122.58 grams of granite is needed to store 1.50 x 10^6 J of heat and increase its temperature by 15.5°C.
To find the mass of granite needed to store 1.50 x 10^6 J of heat with a temperature increase of 15.5°C, we can use the formula:
Q = m * C * ΔT
where:
Q is the heat energy
m is the mass of the substance
C is the specific heat capacity of the substance
ΔT is the change in temperature
In this case, we are given the heat energy (Q) as 1.50 x 10^6 J, the specific heat capacity (C) of granite as 800 J/g∙°C, and the change in temperature (ΔT) as 15.5°C.
Substituting these values into the formula, we have:
1.50 x 10^6 J = m * 800 J/g∙°C * 15.5°C
To solve for the mass (m), we need to rearrange the equation:
m = Q / (C * ΔT)
Now we can substitute the given values:
m = (1.50 x 10^6 J) / (800 J/g∙°C * 15.5°C)
Calculating this expression:
m = 1.50 x 10^6 J / 12400 J/g
m ≈ 120.97 g
Therefore, approximately 120.97 grams of granite is needed to store 1.50 x 10^6 J of heat with a temperature increase of 15.5°C.