Write y - 2 = 3/2 (x+2) in slope Intercept form
To write the equation in slope-intercept form (y = mx + b), we need to isolate y on one side of the equation.
Starting with y - 2 = 3/2(x + 2):
Distribute the 3/2 to both terms inside the parentheses:
y - 2 = 3/2 * x + 3/2 * 2
Simplify the right side:
y - 2 = 3/2 * x + 3
Add 2 to both sides of the equation to isolate y:
y = 3/2 * x + 3 + 2
Simplify:
y = 3/2 * x + 5
The equation in slope-intercept form is y = 3/2x + 5.
To write the equation y - 2 = 3/2 (x + 2) in slope-intercept form, we need to isolate y on one side of the equation.
First, distribute the 3/2 to the terms inside the parentheses:
y - 2 = (3/2)x + 3
Next, we can move the -2 to the right side of the equation by adding 2 to both sides:
y = (3/2)x + 3 + 2
Simplifying, we have:
y = (3/2)x + 5
Therefore, the equation y - 2 = 3/2 (x + 2) in slope-intercept form is y = (3/2)x + 5.
To write the equation in slope-intercept form (y = mx + b), we need to isolate the y-term on one side of the equation by performing the necessary algebraic operations.
Given: y - 2 = (3/2)(x+2)
1. Distribute (3/2) to the terms inside the parentheses:
y - 2 = (3/2)x + (3/2)(2)
Simplify:
y - 2 = (3/2)x + 3
2. Move the constant term (-2) to the right side of the equation by adding 2 to both sides:
y - 2 + 2 = (3/2)x + 3 + 2
Simplify:
y = (3/2)x + 5
Thus, the equation y - 2 = (3/2)(x+2) can be written in slope-intercept form as y = (3/2)x + 5.
The slope of the equation is (3/2), and the y-intercept is the constant term, which is 5.