Determine the concentration of a 25 ml solution of H2SO4 that undergoes titration with
NaOH and reaches the equivalence point after 18 mL of it was added.
To determine the concentration of the H2SO4 solution, we need to use the equation:
c1v1 = c2v2
Where:
c1 = concentration of H2SO4
v1 = volume of H2SO4 used
c2 = concentration of NaOH
v2 = volume of NaOH used
We know that the concentration of NaOH is 1.00 M, and the volume of NaOH used is 18 mL. The volume of H2SO4 used is 25 mL, and we want to find the concentration of H2SO4.
So the equation becomes:
c1 * 25 mL = 1.00 M * 18 mL
To solve for c1, rearrange the equation:
c1 = (1.00 M * 18 mL) / 25 mL
c1 = 0.72 M
Therefore, the concentration of the 25 mL solution of H2SO4 is 0.72 M.
To determine the concentration of the H2SO4 solution, we need to use the equation for acid-base titration.
The balanced chemical equation for the reaction between H2SO4 and NaOH is as follows:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the equation, we can see that the molar ratio between H2SO4 and NaOH is 1:2. This means that one mole of H2SO4 reacts with two moles of NaOH.
Given the volume of NaOH added at the equivalence point is 18 mL, we can determine the number of moles of NaOH used.
18 mL/1000 mL/L = 0.018 L
moles of NaOH = Volume * Concentration = 0.018 L * unknown concentration = unknown concentration * 0.018 moles
Since the molar ratio of H2SO4 to NaOH is 1:2, the number of moles of H2SO4 is half the number of moles of NaOH.
moles of H2SO4 = 0.018 moles/2 = 0.009 moles
Now, we can determine the concentration of H2SO4 in the solution.
Concentration of H2SO4 = moles of H2SO4 / Volume of H2SO4 solution
Concentration of H2SO4 = 0.009 moles / 0.025 L = 0.36 moles/L
Therefore, the concentration of the 25 mL solution of H2SO4 is 0.36 moles/L.
To determine the concentration of the H2SO4 solution, we need to use the information provided about the titration and the balanced chemical equation between H2SO4 and NaOH.
The balanced chemical equation between H2SO4 and NaOH is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the balanced equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH. This means that the number of moles of NaOH consumed in the titration is equal to half the number of moles of H2SO4 present in the solution at the equivalence point.
First, we need to calculate the number of moles of NaOH used. We know that 18 mL of NaOH was added to reach the equivalence point. Assuming the concentration of NaOH is known, we can calculate the number of moles of NaOH used.
Next, we use the stoichiometry of the balanced equation to calculate the number of moles of H2SO4. Since 1 mole of H2SO4 reacts with 2 moles of NaOH, the number of moles of H2SO4 is equal to half the number of moles of NaOH.
Finally, to determine the concentration of the H2SO4 solution, we divide the moles of H2SO4 by the volume of the H2SO4 solution in liters.
Here's the step-by-step calculation:
1. Calculate the number of moles of NaOH used:
Number of moles = (volume of NaOH used / 1000) * concentration of NaOH
For example, if the concentration of NaOH is 0.1 M and 18 mL of NaOH was used:
Number of moles of NaOH = (18 mL / 1000) * 0.1 M
2. Calculate the number of moles of H2SO4:
Number of moles of H2SO4 = 0.5 * Number of moles of NaOH
3. Calculate the concentration of H2SO4:
Concentration of H2SO4 = Number of moles of H2SO4 / (volume of H2SO4 solution / 1000)
For example, if the volume of the H2SO4 solution is 25 mL:
Concentration of H2SO4 = (Number of moles of H2SO4) / (25 mL / 1000)