3 grams of Aluminum was heated from 20 0 C to 662 0 C while absorbing 1728 J of heat. What is the specific heat of Aluminum?
write me a equation
The equation to calculate the specific heat of a substance is:
q = m x c x ΔT
Where:
q = amount of heat absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, we know:
q = 1728 J
m = 3 g
ΔT = 662°C - 20°C = 642°C
Plugging these values into the equation, we get:
1728 J = 3 g x c x 642°C
And rearranging the equation to solve for c, we have:
c = 1728 J / (3 g x 642°C)
Therefore, the equation to calculate the specific heat of Aluminum is:
c = 0.898 J/g°C
To calculate the specific heat of aluminum, we can use the formula:
q = mcΔT
Where:
q = heat absorbed or released by the substance (in joules)
m = mass of the substance (in grams)
c = specific heat of the substance (in J/g°C)
ΔT = change in temperature (in °C)
Given values:
q = 1728 J
m = 3 g
ΔT = 662°C - 20°C = 642°C
The equation becomes:
1728 J = 3 g * c * 642°C
Now, divide both sides of the equation by the product of mass (m) and ΔT:
c = 1728 J / (3 g * 642°C)
Therefore, the equation for calculating the specific heat of aluminum is:
c = 1728 J / (3 g * 642°C)
Sure! The specific heat of a substance is defined as the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius (or Kelvin).
Let's use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat absorbed (in joules),
m is the mass of the substance (in grams),
c is the specific heat of the substance (in joules/gram°C),
ΔT is the change in temperature (in °C).
In this case, we have:
Q = 1728 J,
m = 3 g,
ΔT = (662°C - 20°C) = 642°C
Rearranging the equation to solve for c, we get:
c = Q / (m * ΔT)
Plugging in the given values, the equation becomes:
c = 1728 J / (3 g * 642 °C)
Now we can calculate the specific heat (c).