A patient receives 100 mL of 20% (m/v) mannitol solution every hour.
How many grams of mannitol are given in 1 hour?
Express your answer using two significant figures.
The concentration of the mannitol solution is given as 20% (m/v), which means there are 20 grams of mannitol in every 100 mL of solution.
In 1 hour, the patient receives 100 mL of the mannitol solution.
Therefore, the amount of mannitol given in 1 hour is:
(20 grams/100 mL) x (100 mL) = 20 grams
So, 20 grams of mannitol are given in 1 hour.
To determine the number of grams of mannitol given in one hour, we need to know the concentration of the mannitol solution and the volume given per hour.
Given:
Concentration of mannitol solution = 20% (m/v)
Volume of mannitol solution given per hour = 100 mL
Step 1: Calculate the mass of mannitol in the solution.
The concentration is given as a percentage (m/v), which means 20 g of mannitol is present in 100 mL of the solution.
Step 2: Convert the volume from milliliters to liters.
Since the concentration is given in grams per liter (m/v), we need to convert the volume from milliliters to liters.
100 mL = 100/1000 L = 0.1 L
Step 3: Calculate the mass of mannitol in 1 hour.
To find the mass of mannitol given in one hour, we multiply the concentration (20 g/L) by the volume given per hour (0.1 L).
Mass of mannitol = (20 g/L) x (0.1 L) = 2 g
Therefore, in 1 hour, 2 grams of mannitol are given.
To calculate the number of grams of mannitol that are given in 1 hour, we need to use the concentration and volume of the mannitol solution.
We are given that the concentration of the mannitol solution is 20% (m/v), which means that there are 20 grams of mannitol dissolved in 100 mL of solution.
To calculate the grams of mannitol given in 1 hour, we can use the following formula:
Grams of mannitol = (Concentration/100) * Volume
Given:
Concentration = 20%
Volume = 100 mL
Plugging in the values into the formula:
Grams of mannitol = (20/100) * 100 mL
Simplifying the equation:
Grams of mannitol = 20 grams
Therefore, in 1 hour, 20 grams of mannitol are given.