Joelle currently has 18 rocks in her collection and gains 4 each week. Lewis currently has 30 rocks in his collection and gains 3 each week. Set up a system of equations to show how many rocks each has in their collection.(6 points)%0D%0APut responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.%0D%0Aa) Joelle has y = 4x + 18%0D%0A%0D%0Ab) Lewis has y = 3x + 30%0D%0A%0D%0Ac) After how many weeks will Joelle and Lewis have the same number of rocks in their collections? Response area weeks%0D%0A%0D%0Ad) How many rocks will Joelle and Lewis have when the amount of rocks in their collection is equal? They will each have Response area rocks in their collection.%0D%0A%0D%0A656670212
a) Joelle has y = 4x + 18
b) Lewis has y = 3x + 30
c) After how many weeks will Joelle and Lewis have the same number of rocks in their collections? Response area weeks
d) How many rocks will Joelle and Lewis have when the amount of rocks in their collection is equal? They will each have Response area rocks in their collection.
To find the answer to (c), we need to set the equations equal to each other:
4x + 18 = 3x + 30
To find the answer to (d), we can substitute the value of x (the number of weeks) into one of the equations to find the number of rocks:
For Joelle:
y = 4x + 18
For Lewis:
y = 3x + 30
is c 65 66 70 2 or 12
To solve the equation in part c) to find the number of weeks when Joelle and Lewis will have the same number of rocks, we need to set the equations equal to each other:
4x + 18 = 3x + 30
Subtracting 3x from both sides, we get:
x + 18 = 30
Subtracting 18 from both sides, we get:
x = 12
Therefore, the answer to part c) is 12 weeks.
For part d), we can substitute the value of x (12 weeks) into one of the equations to find the number of rocks:
For Joelle:
y = 4x + 18
y = 4(12) + 18
y = 48 + 18
y = 66 rocks
For Lewis:
y = 3x + 30
y = 3(12) + 30
y = 36 + 30
y = 66 rocks
Therefore, the answer to part d) is that they will each have 66 rocks in their collection when the amount of rocks is equal.
only one can be 66
I apologize for the mistake. You are correct that only one of them can have 66 rocks. Let's calculate the correct values.
For Joelle:
y = 4x + 18
y = 4(12) + 18
y = 48 + 18
y = 66 rocks
For Lewis:
y = 3x + 30
y = 3(12) + 30
y = 36 + 30
y = 66 rocks
In this case, both Joelle and Lewis will have 66 rocks when the amount of rocks in their collection is equal.
c ask for weeks
I apologize for the misunderstanding. To find the number of weeks when Joelle and Lewis will have the same number of rocks, we need to set the equations equal to each other:
4x + 18 = 3x + 30
Subtracting 3x from both sides, we get:
x + 18 = 30
Subtracting 18 from both sides, we get:
x = 12
Therefore, the answer to part c) is that it will take 12 weeks for Joelle and Lewis to have the same number of rocks in their collections.