Consider the function,
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=
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f(x)=2x−1
Use the above function to complete the following table.
To complete the table using the function f(x) = 2x - 1, we need to substitute different values of x into the function and calculate the corresponding values of f(x).
Let's choose different values of x and calculate f(x):
x = -2:
f(-2) = 2(-2) - 1 = -4 - 1 = -5
x = -1:
f(-1) = 2(-1) - 1 = -2 - 1 = -3
x = 0:
f(0) = 2(0) - 1 = 0 - 1 = -1
x = 1:
f(1) = 2(1) - 1 = 2 - 1 = 1
x = 2:
f(2) = 2(2) - 1 = 4 - 1 = 3
Now, we can fill in the table:
x | f(x)
----------------
-2 | -5
-1 | -3
0 | -1
1 | 1
2 | 3
To complete the table, we need to evaluate the function f(x) for different values of x.
Let's choose some values for x and calculate the corresponding f(x) values:
x | f(x)
---------------------
0 | -1
1 | 1
2 | 3
-1 | -3
-2 | -5
To find the values of f(x), we substitute the given values of x into the function f(x) = 2x - 1 and simplify.
For x = 0:
f(0) = 2(0) - 1
= 0 - 1
= -1
For x = 1:
f(1) = 2(1) - 1
= 2 - 1
= 1
For x = 2:
f(2) = 2(2) - 1
= 4 - 1
= 3
For x = -1:
f(-1) = 2(-1) - 1
= -2 - 1
= -3
For x = -2:
f(-2) = 2(-2) - 1
= -4 - 1
= -5
Therefore, the completed table is:
x | f(x)
---------------------
0 | -1
1 | 1
2 | 3
-1 | -3
-2 | -5
To complete the table, you need to plug in different values for x into the function f(x) = 2x - 1 and compute the corresponding outputs.
Let's start by choosing some values for x and then calculate f(x):
x = -2:
f(-2) = 2(-2) - 1 = -4 - 1 = -5
x = -1:
f(-1) = 2(-1) - 1 = -2 - 1 = -3
x = 0:
f(0) = 2(0) - 1 = 0 - 1 = -1
x = 1:
f(1) = 2(1) - 1 = 2 - 1 = 1
x = 2:
f(2) = 2(2) - 1 = 4 - 1 = 3
Now we can complete the table:
| x | f(x) |
| -2 | -5 |
| -1 | -3 |
| 0 | -1 |
| 1 | 1 |
| 2 | 3 |
So, the completed table for the function f(x) = 2x - 1 is:
| x | f(x) |
| -2 | -5 |
| -1 | -3 |
| 0 | -1 |
| 1 | 1 |
| 2 | 3 |