A hot air balloon leaves the ground and rises to an elevation of 1,100 ft. During the next 30 minutes it descends 500 feet, rises 950 feet, descends 375 feet, and finally passes over a school. What is the elevation of the balloon when it passes over the school?
1,025
1,100
1,175
1,550
To find the elevation of the balloon when it passes over the school, we need to calculate the net change in elevation during the entire journey.
Initially, the balloon rises to an elevation of 1,100 ft.
Then, it descends 500 ft, which results in a decrease in elevation.
Next, it rises 950 ft, which results in an increase in elevation.
Then, it descends 375 ft, which again results in a decrease in elevation.
Since we only want to find the elevation when the balloon passes over the school, we don't need to consider the initial rise to 1,100 ft.
So, the net change in elevation is -500 + 950 - 375 = 75 ft.
Therefore, the elevation of the balloon when it passes over the school is 1,100 ft + 75 ft = 1,175 ft.
Hence, the answer is 1,175.
To find the elevation of the balloon when it passes over the school, we need to calculate the net change in elevation after each step.
Given:
Initial elevation: 1,100 ft
Descend: -500 ft
Rise: +950 ft
Descend: -375 ft
Net change in elevation:
Initial elevation + Descend + Rise + Descend
1,100 ft + (-500 ft) + 950 ft + (-375 ft)
Simplifying the equation:
1,100 ft - 500 ft + 950 ft - 375 ft
= 2,075 ft - 875 ft
= 1,200 ft
Therefore, the elevation of the balloon when it passes over the school is 1,200 ft.
To find the elevation of the balloon when it passes over the school, we need to track the changes in elevation step by step.
1. Start with the initial elevation: The balloon leaves the ground and rises to an elevation of 1,100 ft.
2. Descend 500 feet: Subtract 500 from the current elevation of 1,100 ft. This gives us 1,100 - 500 = 600 ft.
3. Rise 950 feet: Add 950 to the current elevation of 600 ft. This gives us 600 + 950 = 1,550 ft.
4. Descend 375 feet: Subtract 375 from the current elevation of 1,550 ft. This gives us 1,550 - 375 = 1,175 ft.
Therefore, the elevation of the balloon when it passes over the school is 1,175 ft.