What is the irrational square root 28−−√ simplified?(1 point)
The irrational square root of 28 simplified is 2√7.
To simplify the irrational square root of 28, we need to find any perfect square factors of 28 that we can remove from under the square root.
First, let's factorize 28:
28 = 2 x 2 x 7
Notice that there are two factors of 2, which is a perfect square. We can rewrite the expression like this:
√(28) = √(2 x 2 x 7)
Now, we can take out the perfect square factor of 2 from under the square root:
√(28) = √(2 x 2 x 7) = √(2 x 2) x √(7)
Simplifying further, we get:
√(28) = 2√(7)
So, the simplified form of the irrational square root of 28 is 2√(7).
To simplify the irrational square root of 28, we can look for perfect square factors of 28.
The prime factorization of 28 is 2 * 2 * 7.
We can rewrite 28 as (4 * 7), where 4 is a perfect square (2 * 2).
Now we can simplify the square root of 28 as the square root of (4 * 7).
Using the property √(a * b) = √a * √b, we can rewrite the expression as √4 * √7.
The square root of 4 is 2, so the simplified form of the square root of 28 is 2√7.