write 0.4x+0.2y =0.6 in slope -intercept form
y=
-2x + 3
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form (y = mx + b), we need to isolate the y-term on one side of the equation.
Step 1: Subtract 0.4x from both sides of the equation:
0.2y = -0.4x + 0.6
Step 2: Divide both sides of the equation by 0.2 to isolate the y-term:
y = (-0.4/0.2)x + (0.6/0.2)
Step 3: Simplify:
y = -2x + 3
So, the equation 0.4x + 0.2y = 0.6 can be written in slope-intercept form as y = -2x + 3.
To convert the equation 0.4x + 0.2y = 0.6 into slope-intercept form, which is in the form y = mx + b, where m represents the slope and b represents the y-intercept, we need to isolate y on one side of the equation.
Let's start by moving the 0.4x term to the other side of the equation:
0.4x + 0.2y = 0.6
0.2y = -0.4x + 0.6
To isolate y, divide every term by 0.2:
y = (-0.4/0.2)x + 0.6/0.2
Simplifying further:
y = -2x + 3
Therefore, the equation 0.4x + 0.2y = 0.6 can be written in slope-intercept form as y = -2x + 3.