Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope?(1 point)

Responses

The newtons are in the same direction, so the newtons can be multiplied.
The newtons are in the same direction, so the newtons can be multiplied.

The forces are in the same direction, so the newtons can be added.
The forces are in the same direction, so the newtons can be added.

The forces are in opposite directions, so the newtons can be divided.
The forces are in opposite directions, so the newtons can be divided.

The forces are in opposite directions, so the newtons can be subtracted.

The forces are in opposite directions, so the newtons can be subtracted.

The correct answer is "The forces are in opposite directions, so the newtons can be subtracted." to determine the net force on the rope.

To calculate the net force, you need to consider both the magnitude and direction of the forces applied. In this case, there are two groups of children pulling in opposite directions with different forces.

First, let's assign positive values for forces in one direction and negative values for forces in the opposite direction. We can take the force exerted by the five children as +10 N, and the force exerted by the ten children as -15 N.

To find the net force, you need to subtract the force exerted in the opposite direction from the force exerted in the desired direction. So, the equation for calculating the net force would be:

Net Force = 10 N - 15 N

This simplifies to:

Net Force = -5 N

Therefore, the net force on the rope in this tug-of-war game is -5 newtons.

The forces are in opposite directions, so the newtons can be subtracted.