Round to the nearest tenth
A is unknown
16
12
C2-B2=A2
C2-B2=A2
16-12=A2
4=A2
To solve for A, we need to find the square root of both sides of the equation:
A = √4
A = 2
So, A is 2.
To find the value of A rounded to the nearest tenth, we need to solve the equation C^2 - B^2 = A^2.
Let's assume that C = 16 and B = 12.
Plugging in these values, we have 16^2 - 12^2 = A^2.
Simplifying, we get 256 - 144 = A^2.
Therefore, 112 = A^2.
To find the value of A, we need to take the square root of both sides.
√(112) = √(A^2)
Taking the square root, we get A ≈ 10.583.
Rounded to the nearest tenth, A is approximately 10.6.
To solve this equation and find the value of A, we need to first calculate the values of C^2 and B^2. After that, we can subtract B^2 from C^2 to get the value of A^2. Finally, we can take the square root of A^2 to find the value of A.
Let's break down the steps:
1. Calculate C^2: Multiply the number C by itself (C x C).
For example, if C is 16, then C^2 = 16 x 16 = 256.
2. Calculate B^2: Multiply the number B by itself (B x B).
For example, if B is 12, then B^2 = 12 x 12 = 144.
3. Calculate A^2: Subtract the value of B^2 from the value of C^2 (C^2 - B^2).
Using the values from the previous steps, A^2 = 256 - 144 = 112.
4. Calculate A: Take the square root of A^2 (√A^2).
Using the value from the previous step, A = √112.
Now, round the value of A to the nearest tenth by considering the decimal places:
- If the digit in the hundredth place (first decimal place) is 5 or above, round up. Otherwise, round down.
For example, if A = √112, then A ≈ 10.583.
Rounding to the nearest tenth, A = 10.6.
Therefore, the rounded value of A to the nearest tenth is 10.6.