Two forces act on an object. One force has a magnitude of 30N directed west, and the other force has a magnitude of 12 N directed east. What is the net force on the object?(1 point)%0D%0AResponses%0D%0A%0D%0A42N west%0D%0A42N west%0D%0A%0D%0A42 N east%0D%0A42 N east%0D%0A%0D%0A18N west%0D%0A18N west%0D%0A%0D%0A18N east
The net force on the object is the vector sum of the two forces. Since the two forces have opposite directions, we need to subtract the magnitude of the smaller force from the larger force.
|30N| - |12N| = 30N - 12N = 18N
Therefore, the net force on the object is 18N directed west.
The correct response is 18N west.
To find the net force on the object, we need to add the individual forces acting on it. Since one force is in the west direction and the other is in the east direction, we can subtract their magnitudes to determine the net force.
The force with a magnitude of 30N directed west is negative since it opposes the positive east direction. So, it can be represented as -30N.
The force with a magnitude of 12N directed east is already positive since it matches the direction. So, it can be represented as +12N.
To find the net force, we subtract the magnitudes: +12N - 30N = -18N.
Therefore, the net force on the object is 18N directed west. So the correct response is 18N west.
To find the net force on the object, you need to subtract the smaller force from the larger force.
The force directed west has a magnitude of 30 N, and the force directed east has a magnitude of 12 N.
Thus, the net force on the object is 30 N - 12 N = 18 N west.
So the correct answer is 18N west.