Suppose 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2
). According to the law of conservation of matter, how many atoms are present in this reaction?(1 point)
Responses
15
15
30
30
20
20
10
The correct response is 30.
To determine the number of atoms present in the reaction, we need to calculate the total number of atoms in each molecule involved.
In this reaction, we have 10 atoms of carbon (C) reacting with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
Let's break down the molecules involved:
1 molecule of carbon dioxide (CO2) consists of 1 atom of carbon (C) and 2 atoms of oxygen (O).
Therefore, 10 molecules of carbon dioxide (CO2) will contain:
10 x 1 carbon atom = 10 carbon atoms
10 x 2 oxygen atoms = 20 oxygen atoms
Adding up the total number of carbon and oxygen atoms:
10 carbon atoms + 20 oxygen atoms = 30 atoms
So, according to the law of conservation of matter, there are 30 atoms present in this reaction.
To find out how many atoms are present in this reaction, we need to calculate the total number of atoms in the reactants and products.
The given reaction is:
10 atoms of carbon (C) + 20 atoms of oxygen (O) → 10 molecules of carbon dioxide (CO2)
In one molecule of carbon dioxide (CO2), there is 1 atom of carbon (C) and 2 atoms of oxygen (O).
So, in 10 molecules of carbon dioxide (CO2), there would be:
10 molecules × 1 atom of carbon (C) = 10 atoms of carbon (C)
10 molecules × 2 atoms of oxygen (O) = 20 atoms of oxygen (O)
In total, there are 10 atoms of carbon (C) and 20 atoms of oxygen (O) in this reaction.
Therefore, the correct answer is:
The number of atoms present in this reaction is 10 + 20 = 30.