Bertha and Vernon are competing in a diving competition. Bertha's dive ended -45 m from the starting platform. Vernon's dive ended -9 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive?(1 point)
Responses
405
405
-36
-36
36
36
5
The correct answer is 5.
To find out how many times farther the end of Bertha's dive is from the end of Vernon's dive, we need to calculate the absolute value of the difference between the two distances and then divide it by the distance of Vernon's dive.
First, let's calculate the absolute difference between the two distances:
|-45 - (-9)| = |-45 + 9| = |-36| = 36
The absolute difference between the two distances is 36 meters.
Now, let's calculate how many times 36 meters is of Vernon's dive:
36 / 9 = 4
So, the end of Bertha's dive was 4 times farther than the end of Vernon's dive.
To find out how many times farther Bertha's dive ended from the starting platform compared to Vernon's dive, we need to calculate the ratio between the two distances.
First, let's find the absolute values of the distances from the starting platform for both dives. Since the question mentions that both distances are negative, we can ignore the negative signs and calculate the absolute values. The absolute value of -45 is 45, and the absolute value of -9 is 9.
Now, we can calculate the ratio by dividing the larger distance by the smaller distance: 45 ÷ 9 = 5.
So, Bertha's dive ended 5 times farther from the starting platform than Vernon's dive.
Therefore, the answer is 5.