A hot air balloon leaves the ground and rise to an elevation of 1100 feet. During the next 30 minutes descends 500 feet, rises 950 feet, descends 375 feet, finally passes over school. What is the elevation of the balloon when it passes over the school?
To find the elevation of the balloon when it passes over the school, we need to add up all the changes in elevation.
The balloon rises to an elevation of 1100 feet.
Then, it descends 500 feet, so the elevation becomes 1100 - 500 = 600 feet.
Next, it rises another 950 feet, so the elevation becomes 600 + 950 = 1550 feet.
It then descends 375 feet, so the final elevation is 1550 - 375 = 1175 feet.
Therefore, the elevation of the balloon when it passes over the school is 1175 feet.
To find the elevation of the balloon when it passes over the school, we need to keep track of the changes in elevation.
First, let's start with the initial elevation:
- The hot air balloon leaves the ground, so the initial elevation is 0 feet.
Next, let's look at the changes in elevation:
- The balloon rises to an elevation of 1100 feet.
- It then descends 500 feet, bringing the elevation to 1100 - 500 = 600 feet.
- Next, it rises 950 feet, bringing the elevation to 600 + 950 = 1550 feet.
- Finally, it descends 375 feet, bringing the elevation to 1550 - 375 = 1175 feet.
Therefore, the elevation of the balloon when it passes over the school is 1175 feet.
To find the elevation of the balloon when it passes over the school, we need to calculate the net change in the elevation.
Starting elevation: 0 feet
Rise to 1100 feet: +1100 feet
Descend 500 feet: -500 feet
Rise 950 feet: +950 feet
Descend 375 feet: -375 feet
Now let's calculate the net change:
1100 - 500 + 950 - 375 = 1175 feet
Therefore, the elevation of the balloon when it passes over the school is 1175 feet.