a=9
b=40
c=?
A2+B2=C2
Show short answer work
Given that a = 9 and b = 40, let's find the value of c using the Pythagorean theorem:
a^2 + b^2 = c^2
9^2 + 40^2 = c^2
81 + 1600 = c^2
1681 = c^2
Taking the square root of both sides, we get:
c = √1681
c ≈ 41
Therefore, the value of c is approximately 41.
To find the value of c in the equation A^2 + B^2 = C^2, where A = 9 and B = 40, we can substitute the given values into the equation and solve for c.
First, square the values of A and B:
A^2 = 9^2 = 81
B^2 = 40^2 = 1600
Now, substitute these values into the equation:
81 + 1600 = C^2
Combine the numbers on the left side:
1681 = C^2
To solve for C, we need to find the square root of both sides:
√1681 = √C^2
Taking the square root of 1681 gives us:
41 = C
So, the value of c is 41.
To find the value of C, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (C) is equal to the sum of the squares of the other two sides (A and B).
Given:
A = 9
B = 40
Using the Pythagorean theorem, we can calculate C^2 as follows:
C^2 = A^2 + B^2
C^2 = 9^2 + 40^2
C^2 = 81 + 1600
C^2 = 1681
Taking the square root of both sides, we can find the value of C:
C = √1681
The short answer is that C = 41.