Write 0.4x+0.2y=0.6
in slope-intercept form.(1 point)
y=
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form, simply isolate the y variable on one side of the equation.
0.4x + 0.2y = 0.6
Subtract 0.4x from both sides:
0.2y = -0.4x + 0.6
Now, divide both sides by 0.2:
y = -2x + 3
Therefore, the equation 0.4x + 0.2y = 0.6 in slope-intercept form is y = -2x + 3.
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form (which is of the form y = mx + b, where m is the slope and b is the y-intercept), we need to isolate y on one side of the equation.
First, let's move the 0.4x term to the right side by subtracting 0.4x from both sides of the equation:
0.2y = -0.4x + 0.6
Next, to get y by itself, we can divide both sides of the equation by 0.2:
y = (-0.4x + 0.6)/0.2
Simplifying the right side of the equation gives us:
y = -2x + 3
So, the equation 0.4x + 0.2y = 0.6 in slope-intercept form is y = -2x + 3.
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form, we need to isolate y on one side of the equation.
First, let's move the term 0.4x to the right-hand side of the equation by subtracting 0.4x from both sides:
0.2y = -0.4x + 0.6
Next, let's isolate y by dividing both sides of the equation by 0.2:
y = (-0.4x + 0.6) / 0.2
Simplifying the right-hand side gives:
y = -2x + 3
Therefore, the equation 0.4x + 0.2y = 0.6 can be written in slope-intercept form as y = -2x + 3.