Subtract: (3b−2c)−(6c+2b)−(b+c) .
By applying the associative property, we can combine like terms within each set of parentheses:
(3b - 2c) - (6c + 2b) - (b + c) = 3b - 2c - 6c - 2b - b - c
Then, we can rearrange the terms by grouping like terms:
= (3b - 2b - b) + (-2c - 6c - c)
= (3 - 2 - 1)b + (-2 - 6 - 1)c
Simplifying further:
= 0b - 9c
= -9c
To subtract the given expression, you need to perform the subtraction operation within each parentheses and then combine like terms.
Step 1: Subtract within the first set of parentheses (3b-2c) - (6c+2b):
- Distribute the negative sign to each term inside the second set of parentheses:
3b - 2c - 6c - 2b
- Combine like terms:
(3b - 2b) + (-2c - 6c)
b - 8c
Step 2: Subtract the result from step 1 from the last set of parentheses (b+c):
- Distribute the negative sign to each term inside the last set of parentheses:
b + c - (b - 8c)
- Remove parentheses and distribute the negative sign to each term inside:
b + c - b + 8c
- Combine like terms:
(b - b) + (8c + c)
8c + c
9c
Therefore, the subtraction of (3b - 2c) - (6c + 2b) - (b + c) simplifies to 9c.
To subtract the given expression: (3b−2c)−(6c+2b)−(b+c), we first need to distribute the negative sign to each term inside the parentheses.
Let's start:
(3b - 2c) - (6c + 2b) - (b + c)
= 3b - 2c - 6c - 2b - b - c
Next, we can combine like terms. That means we group the variables with the same letters together and then evaluate them.
3b - 2b - b - 2c - 6c - c
= (3b - 2b - b) + (-2c - 6c - c)
Simplifying the coefficients, we have:
= (3 - 2 - 1)b + (-2 - 6 - 1)c
= 0b - 9c
Since 0 times any value is 0, we have:
= 0 - 9c
= -9c
Therefore, the answer to the subtraction expression (3b−2c)−(6c+2b)−(b+c) is -9c.