Balance the following equation:
C(s)+o2(g)->co3(g)
a
2, 1, 1
b
2, 3, 2
c
1, 1, 1
d
3, 3, 2
The correct balanced equation is:
C(s) + 3O2(g) -> 2CO3(g)
So, the answer is d) 3, 3, 2.
To balance the equation C(s) + O2(g) -> CO3(g), we need to ensure that the number of atoms on both sides of the equation are equal.
The correct coefficients are:
C(s) + O2(g) -> 2CO3(g)
This means that there is 1 carbon atom and 2 oxygen atoms on the left side of the equation, and 2 carbon atoms and 6 oxygen atoms on the right side of the equation. By adding the correct coefficients, the number of atoms on both sides of the equation is now balanced. Therefore, the correct answer is:
b) 2, 3, 2
To balance the given equation:
C(s) + O2(g) -> CO3(g)
We need to make sure that the number of atoms of each element present in the reactants is equal to the number of atoms of each element in the products.
Let's start by first balancing carbon (C) atoms. There is currently 1 carbon atom on the reactant side and 1 carbon atom on the product side. The coefficient of C(s) will remain as 1.
Next, let's balance oxygen (O) atoms. There are 2 oxygen atoms in the O2 molecule on the reactant side, and 3 oxygen atoms in the CO3 molecule on the product side. To balance the oxygen atoms, we need to have the same number on both sides.
To achieve this, we'll need to put a coefficient of 3 in front of the O2 molecule on the reactant side, so it becomes 3O2. Now, we have 6 oxygen atoms on the reactant side and 3 oxygen atoms on the product side.
The balanced equation is:
C(s) + 3O2(g) -> CO3(g)
Now, let's count the number of each type of atom on both sides of the equation:
Reactant side:
C: 1 atom
O: 3 x 2 = 6 atoms
Product side:
C: 1 atom
O: 3 atoms
We can see that the number of atoms for each element is now equal on both sides. Therefore, the balanced equation is:
C(s) + 3O2(g) -> CO3(g)
So, the correct option to balance the equation is:
b) 2, 3, 2