12. A finess center offers two payment options for their cliems. The "Member Option requires you to pay 542 as beme a member After that you pay only £2 per fines The "on-Member Option requires you to pay $5.50 per finness clan. For sumber of classes would hate options the same amoun Form B
To determine the number of classes for which both options would cost the same amount, we can set up an equation.
Let's assume the number of classes is x.
For the Member Option, the cost is $542 as become a member plus $2 per class. So the total cost for x classes would be:
542 + 2x.
For the Non-Member Option, the cost is $5.50 per class. So the total cost for x classes would be:
5.50x.
To find when the costs are equal, we can set up the equation:
542 + 2x = 5.50x.
Now we can solve for x:
542 = 5.50x - 2x
542 = 3.50x
x = 542 / 3.50
x ≈ 154.857
Since we cannot have a fraction of a class, we can round down to the nearest whole number, which gives us:
x = 154
Therefore, both payment options would cost the same amount for 154 classes.
To compare the cost of the two payment options, let's assume the number of fitness classes taken is denoted by 'x'.
For the Member Option:
Initial membership fee = $542
Cost per fitness class after membership = $2
Total cost for 'x' fitness classes with the Member Option:
Total Cost = Initial membership fee + (Cost per class * Number of classes)
Total Cost = $542 + ($2 * x)
Total Cost = $542 + 2x
For the Non-Member Option:
Cost per fitness class = $5.50
Total cost for 'x' fitness classes with the Non-Member Option:
Total Cost = Cost per class * Number of classes
Total Cost = $5.50 * x
Total Cost = 5.50x
To find the number of classes where both options have the same cost, we can set the two equations equal to each other and solve for 'x'.
$542 + 2x = 5.50x
Subtract 2x from both sides:
542 = 5.50x - 2x
Combine like terms:
542 = 3.50x
Divide both sides by 3.50:
x = 542 / 3.50
x ≈ 154.86
Therefore, both options have the same cost for approximately 155 fitness classes.
To determine the number of classes for which both payment options would be the same amount, we can set up an equation and solve for the unknown variable.
Let's define the number of classes as 'x'.
For the member option, the cost can be calculated as follows:
Membership fee: £542
Cost per class after becoming a member: £2
Total cost for member option = Membership fee + (Cost per class * Number of classes)
Total cost = £542 + (£2 * x)
For the non-member option, the cost is $5.50 per class:
Total cost for non-member option = Cost per class * Number of classes
Total cost = £5.50 * x
Now we can set up the equation:
£542 + (£2 * x) = £5.50 * x
We can proceed to solve for 'x' by isolating it on one side of the equation.
£542 + (£2 * x) = £5.50 * x
£542 = £5.50 * x - (£2 * x)
£542 = £3.50 * x
x = £542 / £3.50
Calculating this value:
x = 155.43 (rounded to two decimal places)
So, for the member and non-member payment options to be the same amount, you would need to have approximately 155 classes.