Bertha and Vernon are competing in a diving competition. Bertha's dive ended -45 m from the starting platform. Vernon's dive ended -9 m from the starting platform. How many times farther was the end of Bertha's dive than the end of Vernon's dive?(1 point)
Responses
405
405
-36
-36
36
36
5
5
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The end of Bertha's dive was 45 m farther from the starting platform than the end of Vernon's dive. Therefore, the end of Bertha's dive was 45/9 = <<45/9=5>>5 times farther than the end of Vernon's dive. Answer: \boxed{5}.
To find the difference in distance between the end of Bertha's dive and the end of Vernon's dive, we can subtract the two distances.
-45 m - (-9 m) = -45 m + 9 m = -36 m
Therefore, the end of Bertha's dive was 36 meters farther than the end of Vernon's dive.
To find out how many times farther the end of Bertha's dive is compared to the end of Vernon's dive, we can subtract the two distances.
Bertha's dive ended -45 m from the starting platform, while Vernon's dive ended -9 m from the starting platform.
So, the difference between the two distances would be:
-45 m - (-9 m) = -45 m + 9 m = -36 m
Now, since the distances are negative, we need to make them positive to calculate the ratio.
So, the absolute values of the distances would be:
| -36 m | = 36 m
Therefore, the end of Bertha's dive is 36 meters farther than the end of Vernon's dive.