It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula:
1N2 + 3H2 → 2NH3
Which combination of molecules will produce ammonia with no leftovers?
(1 point)
Responses
8N2 and 4H28 cap n sub 2 and 4 cap h sub 2
2N2 and 6H22 cap n sub 2 and 6 cap h sub 2
4N2 and 4H24 cap n sub 2 and 4 cap h sub 2
5N2 and 6H2
The correct combination of molecules that will produce ammonia with no leftovers is:
2N2 and 6H2 (2 molecules of nitrogen and 6 molecules of hydrogen)
To produce ammonia with no leftovers, we need to have an equal number of nitrogen and hydrogen molecules on each side of the equation. Looking at the equation 1N2 + 3H2 → 2NH3, we can see that there are 2 nitrogen molecules and 6 hydrogen molecules on the product side.
So, we need to find a combination of molecules that will give us 2 nitrogen molecules and 6 hydrogen molecules.
Among the given options, the combination that satisfies this condition is:
2N2 and 6H2 (2 molecules of nitrogen and 6 molecules of hydrogen).
Therefore, the correct answer is:
2N2 and 6H2.
To determine which combination of molecules will produce ammonia with no leftovers, we need to find a combination that follows the stoichiometry of the reaction.
According to the reaction equation, 1 molecule of nitrogen (N2) reacts with 3 molecules of hydrogen (H2) to produce 2 molecules of ammonia (NH3).
Let's calculate the number of molecules of ammonia that would be produced using each combination:
1. For 8N2 and 4H2:
Nitrogen: 8 molecules of N2
Hydrogen: 4 molecules of H2
The ratio of N2 to NH3 is 1:2, so using 8 molecules of N2 would produce 8/1 * 2 = 16 molecules of NH3.
But, we only have 4 molecules of H2, so this combination will leave 4-3 = 1 molecule of H2 unreacted.
2. For 2N2 and 6H2:
Nitrogen: 2 molecules of N2
Hydrogen: 6 molecules of H2
The ratio of N2 to NH3 is 1:2, so using 2 molecules of N2 would produce 2/1 * 2 = 4 molecules of NH3.
The ratio of H2 to NH3 is 3:2, so using 6 molecules of H2 would produce 6/3 * 2 = 4 molecules of NH3.
This combination produces the exact number of ammonia molecules required, with no leftovers.
3. For 4N2 and 4H2:
Nitrogen: 4 molecules of N2
Hydrogen: 4 molecules of H2
The ratio of N2 to NH3 is 1:2, so using 4 molecules of N2 would produce 4/1 * 2 = 8 molecules of NH3.
The ratio of H2 to NH3 is 3:2, so using 4 molecules of H2 would produce 4/3 * 2 = 2.67 (~3) molecules of NH3.
This combination would leave 8-3 = 5 molecules of NH3 unproduced.
4. For 5N2 and 6H2:
Nitrogen: 5 molecules of N2
Hydrogen: 6 molecules of H2
The ratio of N2 to NH3 is 1:2, so using 5 molecules of N2 would produce 5/1 * 2 = 10 molecules of NH3.
The ratio of H2 to NH3 is 3:2, so using 6 molecules of H2 would produce 6/3 * 2 = 4 molecules of NH3.
This combination would leave 10-4 = 6 molecules of NH3 unproduced.
Therefore, the combination of 2 molecules of N2 and 6 molecules of H2 will produce ammonia with no leftovers.