A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point) Responses 1.6 N 1.6 N 8.2 N 8.2 N 40 N 40 N 7.8 N 7.8 N
The force (F) can be calculated using the equation F = m*a, where m is the mass and a is the acceleration.
Given:
m = 0.2 kg
a = 8 m/s^2
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 N.
To find the force with which the ball hits the catcher's mitt, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the formula:
F = m * a
Substituting the given values:
F = 0.2 kg * 8 m/s^2
Calculating:
F = 1.6 N
Therefore, the force with which the ball hits the catcher's mitt is 1.6 N.
To determine the force with which the ball will hit the catcher's mitt, you can apply Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this scenario, the mass of the softball is given as 0.2 kilograms, and the acceleration is 8 meters per second squared.
Therefore, the force can be calculated as follows:
F = m * a
F = 0.2 kg * 8 m/s²
F = 1.6 N
So, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.