Use the unbalanced chemical equation to answer the question.
2NaHC*O_{3} -> N*a_{2}*C*O_{3} + C*O_{2}
Which of the following can be added to the products to balance the equation?
(1 point)
O H_{2}
H_{2}*O
O C*H_{2}*OH
O O_{2}
The correct answer is O2.
To balance the equation, you need to have an equal number of atoms on both sides of the equation. In this case, there are two oxygen atoms on the reactant side (NaHCO3) and only one oxygen atom on the product side (Na2CO3). By adding O2 to the products, you can balance the equation and have two oxygen atoms on both sides:
2NaHCO3 -> Na2CO3 + CO2 + O2
To balance the given chemical equation, we need to have the same number of atoms of each element on both sides of the equation. The unbalanced equation is:
2NaHCO3 -> Na2CO3 + CO2
To balance it, we'll focus on balancing the carbon (C) and oxygen (O) atoms first.
Looking at the products, we can see that there are already two carbon (C) atoms on the right side. This means we need two carbon (C) atoms on the left side as well.
To balance the oxygen (O) atoms, we count 5 oxygen (O) atoms on the right side (3 from Na2CO3 and 2 from CO2). Therefore, we need 5 oxygen (O) atoms on the left side.
Now, let's analyze the options:
(1) O H2: This option does not contain carbon (C) or provide any additional oxygen (O) atoms, so it cannot be added to balance the equation.
(2) H2O: This option contains oxygen (O) and hydrogen (H) atoms. While it provides the necessary oxygen (O) atoms, it does not contain carbon (C), so it cannot be added to balance the equation.
(3) O C2H6OH: This option contains carbon (C) and oxygen (O) atoms. However, it also contains hydrogen (H) and these elements are not required to balance the equation.
(4) O2: This option contains only oxygen (O) atoms. By adding O2 to the left side of the equation, we can balance the oxygen (O) atoms. Thus, option (4) O2 can be added to the products to balance the equation.
Therefore, the correct answer is option (4) O2.
To balance the given chemical equation, we need to ensure that the same number of each type of atom appears on both sides of the equation. Let's analyze the equation and identify the atoms that are unbalanced:
On the reactant side:
- 2 Na
- 2 H
- 2 C
- 6 O
On the product side:
- 2 Na
- 1 N
- 1 C
- 5 O
From this analysis, we see that the reactant side has more oxygen (6) compared to the product side (5). To balance the equation, we need to add an oxygen-containing compound to the product side.
Now let's evaluate each of the options provided:
1) O H_{2}: This option represents water (H_{2}O), which contains an oxygen atom. Adding water to the products would balance the equation.
2) H_{2}*O: This option represents a hypothetical compound, which would not be valid in a chemical equation.
3) O C*H_{2}*OH: This option represents ethanol (C*H_{3}*OH), which contains an oxygen atom. Adding ethanol to the products would balance the equation.
4) O O_{2}: This option represents oxygen gas (O_{2}). Adding oxygen gas to the products would increase the number of oxygen atoms but not balance the equation since it does not contain any other elements.
Based on this analysis, the correct option that can be added to the products to balance the equation is O H_{2}, which represents water (H_{2}O).