A pilot is flying an airplane. Due to strong winds, the pilot decides to fly 4,000 feet lower to avoid excessive turbulence. It takes the pilot 3.5 minutes to make this adjustment. Interpret the quotient to describe the rate of change in the plane’s altitude. Give your answer to the nearest hundredth, and remember the plane is descending.(1 point) The quotient that best represents the rate of change in the plane’s altitude is feet/minute.
To find the rate of change in the plane's altitude, we can divide the change in altitude by the time it takes for the adjustment. The change in altitude is 4,000 feet (since the pilot is flying 4,000 feet lower), and the time it takes for the adjustment is 3.5 minutes.
So, the rate of change in the plane's altitude is 4,000 feet / 3.5 minutes.
To the nearest hundredth, this is approximately 1142.86 feet/minute.
Therefore, the quotient that best represents the rate of change in the plane's altitude is 1142.86 feet/minute.
To find the rate of change in the plane's altitude, we need to divide the change in altitude by the time it takes for the adjustment.
The change in altitude is 4,000 feet (because the plane is flying 4,000 feet lower).
The time it takes for the adjustment is 3.5 minutes.
To find the rate of change, we divide the change in altitude by the time:
Rate of change = Change in altitude / Time
Rate of change = 4,000 feet / 3.5 minutes
Calculating the quotient, the rate of change is approximately 1142.86 feet/minute.
Rounded to the nearest hundredth, the rate of change in the plane's altitude is approximately 1142.86 feet/minute.
To find the rate of change in the plane's altitude, we need to divide the change in altitude (4,000 feet) by the time it took to make the adjustment (3.5 minutes).
Rate of Change = Change in Altitude / Time
Rate of Change = 4,000 feet / 3.5 minutes
To calculate this, divide 4,000 by 3.5:
Rate of Change ≈ 1142.86 feet/minute
Therefore, the rate of change in the plane's altitude is approximately 1142.86 feet/minute (rounded to the nearest hundredth).