f)
Now that you have an additional $300, revise your inequality from part a to reflect your new spending limit. Solve this inequality. Make sure to round to the nearest dollar.
* Do not include the dollar symbol in the inequality
You can copy and paste the inequality sign below in your answer.
≥ < > ≤
*
1 point
$x + 2250 ≤ 3000$
To revise the spending limit inequality, we need to add the additional $300 to the original spending limit.
Let's assume the original spending limit from part (a) is represented by the variable "x." The original inequality from part (a) was:
x ≤ 800
To revise this inequality with the additional $300, we will add 300 to both sides of the inequality:
x + 300 ≤ 800 + 300
Simplifying, we have:
x + 300 ≤ 1100
Therefore, the revised inequality with the new spending limit of $1100 is:
x ≤ 1100
Now, to solve this inequality, we need to figure out the possible values of x.
Since the inequality involves the less than or equal to (≤) sign, it means that any value of x that is less than or equal to 1100 will satisfy the inequality.
Therefore, the solution to the inequality is:
x ≤ 1100
To round to the nearest dollar, if necessary, we would represent the solution as:
x ≤ $1100 (rounded to the nearest dollar)
Please note that this answer assumes that the original spending limit was given as an inequality of less than or equal to (≤), as indicated in part (a). If the original spending limit was given differently, please provide the correct information, and I will be happy to adjust the explanation accordingly.
To revise the inequality from part a to reflect the new spending limit, we need to subtract the additional $300 from the previous inequality. Let's assume the original inequality was:
x ≤ 1500
To include the additional $300, we subtract it from both sides:
x - 300 ≤ 1500 - 300
This simplifies to:
x - 300 ≤ 1200
Therefore, the revised inequality with the new spending limit is:
x ≤ 1200
To solve this inequality, we do not need to make any rounding adjustments since it already states "less than or equal to". The solution is that x should be less than or equal to 1200.