Solve the following real-world problem: Ahmadullah's Basketball team will play 21 games this season. that 12 more games than 1/3 the number of games they played last season. How many games did they play last season
Let x be the number of games Ahmadullah's basketball team played last season.
We know that 21 = x/3 + 12.
Subtracting 12 from both sides, we get 9 = x/3.
Multiplying both sides by 3, we get x = 27.
Therefore, Ahmadullah's basketball team played 27 games last season. Answer: \boxed{27}.
Let's assume the number of games they played last season is represented by "x".
According to the problem, Ahmadullah's Basketball team will play 21 games this season. This is 12 more games than 1/3 the number of games they played last season.
So, we can set up the equation:
21 = (1/3)x + 12
To solve for x, we can start by subtracting 12 from both sides of the equation:
21 - 12 = (1/3)x
Simplifying the left side:
9 = (1/3)x
To isolate x, we can multiply both sides of the equation by 3:
3 * 9 = 3 * (1/3)x
27 = x
Therefore, Ahmadullah's Basketball team played 27 games last season.
To solve this problem, we can set up an equation based on the information given.
Let's assume the number of games played last season is represented by the variable "x".
According to the problem, Ahmadullah's team will play 21 games this season, which is 12 more than 1/3 of the number of games they played last season.
Using this information, we can create the following equation:
21 = (1/3) * x + 12
To solve for the value of x, let's isolate the variable on one side of the equation:
21 - 12 = (1/3) * x
9 = (1/3) * x
Next, to find the value of x, we can multiply both sides of the equation by 3 to eliminate the fraction:
3 * 9 = 3 * (1/3) * x
27 = x
Therefore, the team played 27 games last season.