Solve the system of equations. 2x+6y=−18 x=5y−1 (1 point) Responses (−6, −1) left parenthesis negative 6 comma negative 1 right parenthesis (5.25, 1.25) left parenthesis 5.25 comma 1.25 right parenthesis (−7.25, −1.25) left parenthesis negative 7.25 comma negative 1.25 right parenthesis (4, 1)
To solve the system of equations, we can substitute the value of x from the second equation into the first equation.
Substituting x = 5y - 1 into the first equation, we get:
2(5y - 1) + 6y = -18
10y - 2 + 6y = -18
16y - 2 = -18
Adding 2 to both sides, we have:
16y = -16
Dividing both sides by 16, we get:
y = -1
Now, substitute this value of y back into the second equation to find x:
x = 5(-1) - 1
x = -5 - 1
x = -6
So, the solution to the system of equations is (-6, -1).
To solve the system of equations, we can substitute the value of x from the second equation into the first equation.
Substituting x = 5y - 1 into the first equation, we get:
2(5y - 1) + 6y = -18
10y - 2 + 6y = -18
16y - 2 = -18
16y = -18 + 2
16y = -16
y = -16/16
y = -1
Now, we can substitute the value of y back into the second equation to find x:
x = 5(-1) - 1
x = -5 - 1
x = -6
Therefore, the solution to the system of equations is (-6, -1).
To solve the system of equations, we can substitute one equation into the other to find the values of x and y.
We have the equations:
1) 2x + 6y = -18
2) x = 5y - 1
Let's substitute equation 2 into equation 1 by replacing x in equation 1 with the expression 5y - 1 from equation 2:
2(5y - 1) + 6y = -18
Distribute 2 to the terms inside the parentheses:
10y - 2 + 6y = -18
Combine like terms:
16y - 2 = -18
Now, let's isolate y by adding 2 to both sides of the equation:
16y - 2 + 2 = -18 + 2
This simplifies to:
16y = -16
Divide both sides by 16 to solve for y:
y = -16 / 16
Simplifying further:
y = -1
Now that we have the value of y, we can substitute it back into equation 2 to find the value of x:
x = 5(-1) - 1
x = -5 - 1
x = -6
Therefore, the solution to the system of equations is (-6, -1).