A tennis player hits a 0.1-kilogram tennis ball with her racket from the north end of a court. Her racket was traveling at 65 kilometers per hour. The ball accelerated at a rate of 10 meters per second squared. The ball hits the floor on the south end of the tennis court. The floor sends the ball toward the tennis player's opponent with the same acceleration. How much force did the floor on the south end of the court exert on the ball?(1 point)
Responses
6.5 N
6.5 N
1 N
1 N
0.01 N
0.01 N
7.5 N
7.5 N
To find the force exerted by the floor on the ball, we can use Newton's second law, which states that force (F) equals mass (m) times acceleration (a).
Given:
Mass of the ball (m) = 0.1 kg
Acceleration (a) = 10 m/s^2
Using the formula F = m * a, we can calculate the force exerted by the floor:
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the floor on the south end of the court exerted a force of 1 N on the ball.
To calculate the force exerted by the floor on the south end of the court on the tennis ball, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).
Given that the mass of the tennis ball is 0.1 kilograms and the acceleration is 10 meters per second squared, we can substitute these values into the formula:
F = m * a
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the force exerted by the floor on the south end of the court on the tennis ball is 1 N.
To find the force exerted by the floor on the ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the ball is given as 0.1 kilograms, and the acceleration is given as 10 meters per second squared.
So, we can calculate the force exerted by the floor using the formula:
F = m * a
F = 0.1 kg * 10 m/s^2
F = 1 N
Therefore, the floor on the south end of the tennis court exerts a force of 1 Newton on the ball.