What is the efficiency of a ramp if 2,000 joules of energy results in 1,200 joules of work?(1 point)
Responses
60%
60%
32%
32%
24%
24%
80%
The efficiency of a ramp can be calculated using the formula:
Efficiency = (Useful Energy Output / Total Energy Input) * 100
In this case, the useful energy output is 1,200 joules and the total energy input is 2,000 joules.
Efficiency = (1,200 / 2,000) * 100 = 60%
Therefore, the correct answer is:
60%
To find the efficiency of a ramp, we can use the formula:
Efficiency = (Output Work / Input Energy) x 100%
Given that 2,000 joules of energy results in 1,200 joules of work, we can substitute these values into the formula to find the efficiency:
Efficiency = (1,200 joules / 2,000 joules) x 100%
Efficiency = 0.6 x 100%
Efficiency = 60%
Therefore, the efficiency of the ramp is 60%.
To determine the efficiency of a ramp, we need to divide the amount of useful work (output) by the amount of energy put into the system (input). In this case, the useful work is 1,200 joules and the energy input is 2,000 joules.
To calculate the efficiency, we use the formula: Efficiency = (Output / Input) x 100%
So, Efficiency = (1,200 joules / 2,000 joules) x 100% = 0.6 x 100% = 60%
Therefore, the efficiency of the ramp is 60%.