The average human heart beats about 3.5x10^7 times per year. The current population of Massachusetts is about 7x10^6 people. About how many heart beats occur in Massachusetts per year? Express the answer to the exact decimal place.
To find the total number of heartbeats that occur in Massachusetts per year, we need to multiply the number of heartbeats per person per year by the population of Massachusetts.
Number of heartbeats per person per year = 3.5 * 10^7
Population of Massachusetts = 7 * 10^6
Total number of heartbeats in Massachusetts per year = (3.5 * 10^7) * (7 * 10^6)
= 24.5 * 10^13
= 2.45 * 10^14
So, there are approximately 2.45 * 10^14 heartbeats that occur in Massachusetts per year.
To calculate the total number of heartbeats that occur in Massachusetts every year, we can multiply the average number of heartbeats per year by the current population of Massachusetts.
Average number of heartbeats per year = 3.5 × 10^7
Current population of Massachusetts = 7 × 10^6
Multiplying these two values together, we get:
3.5 × 10^7 heartbeats/year × 7 × 10^6 people
Using the rules of exponents, we can simplify this equation:
(3.5 × 7) × (10^7 × 10^6) = 24.5 × 10^13
Since the decimal point should be placed after the first digit, we express this answer to the exact decimal place:
2.45 × 10^14
Therefore, about 2.45 × 10^14 heartbeats occur in Massachusetts per year.
To find the total number of heartbeats in Massachusetts per year, we need to multiply the average number of heartbeats per year by the population of Massachusetts. Here's how we can calculate it:
1. Calculate the total number of heartbeats per person in a year:
Average number of heartbeats per year = 3.5 x 10^7
2. Calculate the total population of Massachusetts:
Population of Massachusetts = 7 x 10^6
3. Multiply the average number of heartbeats per year by the population of Massachusetts:
Total number of heartbeats in Massachusetts per year = (Average number of heartbeats per year) x (Population of Massachusetts)
Total number of heartbeats in Massachusetts per year = (3.5 x 10^7) x (7 x 10^6)
To calculate this, we can simplify the equation using the law of exponents:
3.5 x 10^7 x 7 x 10^6 = (3.5 x 7) x 10^(7 + 6) = 24.5 x 10^13 = 2.45 x 10^14
Therefore, there are approximately 2.45 x 10^14 heartbeats in Massachusetts per year.