How does a balanced chemical equation demonstrate the Law of Conservation of Mass?(1 point) Responses it shows that only physical changes follow the Law of Conservation of Mass it shows that only physical changes follow the Law of Conservation of Mass it shows that no atoms have been gained or lost during the reaction it shows that no atoms have been gained or lost during the reaction it shows that all compounds remain bonded after the reaction it shows that all compounds remain bonded after the reaction it shows that the properties of the elements stay the same after the reaction

It shows that no atoms have been gained or lost during the reaction.

The correct response is: it shows that no atoms have been gained or lost during the reaction. A balanced chemical equation demonstrates the Law of Conservation of Mass by ensuring that the number of atoms of each element is the same on both sides of the equation. This means that no atoms are created or destroyed during a chemical reaction, and the total mass remains constant.

The correct answer is: "It shows that no atoms have been gained or lost during the reaction."

A balanced chemical equation demonstrates the Law of Conservation of Mass because it ensures that the number of atoms of each element is the same on both sides of the equation. In a chemical reaction, atoms are rearranged and bonded together to form new compounds. However, the total number of atoms of each element remains constant before and after the reaction.

To balance a chemical equation, you need to ensure that the number of atoms of each element is equal on both sides. This is achieved by adjusting the coefficients (the numbers in front of the chemical formulas) of each reactant and product. By doing so, you ensure that no atoms are gained or lost during the reaction, thus satisfying the Law of Conservation of Mass.

Balancing a chemical equation often involves adjusting the coefficients and sometimes even adding additional reactants or products to ensure that the number of atoms of each element is the same on both sides. It is a methodical process that requires a good understanding of chemical formulas and the stoichiometry of the reaction.