An art student wants to make a model of the classroom. The length of the classroom is 2.4 times its width. The length of the student’s model is 42 in. What should the width of the model be?
(1 point)
Responses
17.5 in
17.5 in
20.5 in
20.5 in
83.6 in
83.6 in
100.8 in
100.8 in
Let's assume the width of the classroom is 'w'.
According to the problem, the length of the classroom is 2.4 times its width. So, the length of the classroom can be represented as 2.4w.
Now, we are given the length of the student's model as 42 in.
Since the length of the student's model should be equivalent to the length of the actual classroom, we can equate the two lengths:
2.4w = 42
To find the width of the model, we need to solve this equation for 'w':
w = 42 / 2.4 = 17.5
Therefore, the width of the model should be 17.5 in.
Hence, the correct answer is 17.5 in.
To find the width of the model, we need to determine the width of the classroom first.
Let's assume the width of the classroom is x.
According to the given information, the length of the classroom is 2.4 times its width, so the length would be 2.4x.
Given that the length of the student's model is 42 inches, we can set up the following equation:
2.4x = 42
To find the value of x, we divide both sides of the equation by 2.4:
x = 42 / 2.4
Calculating this expression gives us:
x = 17.5
Therefore, the width of the model should be 17.5 inches.
So the correct answer is:
17.5 in
To solve this problem, we need to set up a proportion based on the given information. Let's call the width of the classroom "w".
We know that the length of the classroom is 2.4 times its width, so the length of the classroom would be 2.4w.
We also know that the length of the student's model is 42 inches. Now we can set up the proportion:
Length of the model / Width of the model = Length of the classroom / Width of the classroom
So, we have:
42 / width of the model = 2.4w / w
To solve for the width of the model, we can cross multiply and solve for "w":
42w = 2.4w
Divide both sides of the equation by 2.4:
42w / 2.4 = 2.4w / 2.4
w = 42 / 2.4
w ≈ 17.5
Therefore, the width of the model should be approximately 17.5 inches.