An art student wants to make a model of the classroom. The length of the classroom is 2.4 times its width. The length of the student’s model is 42 in. What should the width of the model be? (1 point)
Let's represent the width of the classroom as "w". According to the problem, the length of the classroom is 2.4 times the width, which means the length is 2.4w.
Now, let's set up an equation to represent this relationship: 2.4w = 42.
To find the width of the model, we need to solve for "w" in the equation. Dividing both sides of the equation by 2.4, we have: w = 42 ÷ 2.4.
Using a calculator or long division, we can find that w ≈ 17.5 (rounded to one decimal place).
Therefore, the width of the model should be approximately 17.5 inches.
To find the width of the model, we need to first determine the length of the actual classroom.
Let's assume the width of the classroom is "x."
According to the problem, the length of the classroom is 2.4 times its width. This means the length of the classroom can be calculated as 2.4 * x.
Since we're given that the length of the student's model is 42 inches, we can set up the following equation:
2.4 * x = 42
To find the width (x), we need to isolate the variable. Divide both sides of the equation by 2.4:
x = 42 / 2.4
Evaluating the expression, we find:
x ≈ 17.5
Therefore, the width of the model should be approximately 17.5 inches.
To find the width of the model, we need to first determine the length of the classroom. We are given that the length of the model is 42 inches.
Since the length of the classroom is 2.4 times its width, we can set up the equation:
Length of the classroom = 2.4 * Width of the classroom
We can now substitute the given length of the model (42 inches) into the equation:
42 inches = 2.4 * Width of the classroom
To find the width of the classroom, we can rearrange the equation:
Width of the classroom = 42 inches / 2.4
Now we can calculate the width of the classroom:
Width of the classroom = 17.5 inches
Therefore, the width of the model should be 17.5 inches.