The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges, C , $500 for the ballroom rental fee and $75 per student, s , for the meal. The Greenhill Country Club charges, C , $1,000 for the ballroom rental fee and $65 per student, s , for the meal. Create a pair of linear equations that represent this real-world problem.(1 point) Responses Regal Hotel: C=500s+75; Greenhill Country Club: C=1,000s+65 Regal Hotel: upper C equals 500 s plus 75 ; Greenhill Country Club: upper C equals 1,000 s plus 65 Regal Hotel: C=75s+1,000; Greenhill Country Club: C=65s+500 Regal Hotel: upper C equals 75 s plus 1,000 ; Greenhill Country Club: upper C equals 65 s plus 500 Regal Hotel: C=75s+500; Greenhill Country Club: C=65s+1,000 Regal Hotel: upper C equals 75 s plus 500 ; Greenhill Country Club: upper C equals 65 s plus 1,000 Regal Hotel: C=1,000s+75; Greenhill Country Club: C=500s+65
The correct answer is:
Regal Hotel: C = 500s + 75
Greenhill Country Club: C = 1000s + 65
Regal Hotel: C = 500s + 75
Greenhill Country Club: C = 1,000s + 65
The correct pair of linear equations that represent this problem is:
Regal Hotel: C = 500s + 75
Greenhill Country Club: C = 1,000s + 65
Explanation:
In the problem, the variable 'C' represents the total cost, and 's' represents the number of students attending the prom.
For the Regal Hotel, the cost includes the ballroom rental fee of $500 (which is a fixed cost) as well as $75 per student for the meal. Hence, the equation is C = 500s + 75.
Similarly, for the Greenhill Country Club, the total cost includes the ballroom rental fee of $1,000 (which is a fixed cost) along with $65 per student for the meal. Therefore, the equation is C = 1,000s + 65.