A)
Find the width of a rectangle with a perimeter of 90 and a length of 15.
(1 point)
90
15
45
30
Let's call the width of the rectangle W.
The perimeter of a rectangle is given by the formula P = 2L + 2W, where L is the length and W is the width.
Given that the length is 15 and the perimeter is 90, we can substitute these values into the formula and solve for W:
90 = 2(15) + 2W
90 = 30 + 2W
2W = 90 - 30
2W = 60
W = 60/2
W = 30
Therefore, the width of the rectangle is 30.
To find the width of the rectangle, we can use the formula for the perimeter of a rectangle, which is
Perimeter = 2 * (Length + Width)
Given that the perimeter is 90 and the length is 15, we can substitute these values into the formula:
90 = 2 * (15 + Width)
Next, we can divide both sides of the equation by 2 to isolate the expression for Width:
45 = 15 + Width
Finally, we can subtract 15 from both sides to solve for Width:
Width = 45 - 15
Therefore, the width of the rectangle is 30.
To find the width of a rectangle with a given perimeter and length, you can use the formula for the perimeter of a rectangle: P = 2w + 2l, where P is the perimeter, w is the width, and l is the length.
In this case, we are given that the perimeter is 90 and the length is 15. We can substitute these values into the formula and solve for the width:
90 = 2w + 2(15)
90 = 2w + 30
Next, we want to isolate the variable w (width) by moving the constant term (30) to the other side of the equation:
90 - 30 = 2w
60 = 2w
Finally, we divide both sides of the equation by 2 to solve for w:
w = 60 / 2
w = 30
Therefore, the width of the rectangle is 30.