(2,4) and (5,8) what's the distance
To find the distance between two points (x1, y1) and (x2, y2), we can use the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Using the given points (2, 4) and (5, 8):
d = √((5 - 2)^2 + (8 - 4)^2)
= √(3^2 + 4^2)
= √(9 + 16)
= √25
= 5
Therefore, the distance between (2, 4) and (5, 8) is 5 units.
To find the distance between two points, you can use the distance formula, which is derived from the Pythagorean theorem. The formula is:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Given the coordinates (2, 4) and (5, 8), we can substitute the values into the formula:
Distance = √((5 - 2)^2 + (8 - 4)^2)
Distance = √(3^2 + 4^2)
Distance = √(9 + 16)
Distance = √25
Therefore, the distance between the two points (2, 4) and (5, 8) is 5.
To find the distance between two points in a coordinate plane, we can apply the distance formula. The distance formula is derived from the Pythagorean theorem and can be used to find the length of the hypotenuse of a right triangle.
The formula is:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Let's plug in the coordinates for the two points given:
Point 1: (2, 4)
Point 2: (5, 8)
Using the formula, we have:
Distance = sqrt((5 - 2)^2 + (8 - 4)^2)
Simplifying the equation, we get:
Distance = sqrt(3^2 + 4^2)
Now, calculate the squared values:
Distance = sqrt(9 + 16)
Adding the values inside the square root:
Distance = sqrt(25)
Taking the square root of 25:
Distance = 5
Therefore, the distance between the points (2, 4) and (5, 8) is 5 units.