A game has players roll either one or two standard dice. Which is the total number of possible different outcomes?
When rolling one standard die, there are 6 possible outcomes (numbers 1 to 6).
When rolling two standard dice, each die has 6 possible outcomes, resulting in a total of 36 possible outcomes (6 outcomes for the first die multiplied by 6 outcomes for the second die).
Therefore, the total number of possible different outcomes when rolling either one or two standard dice is 6 + 36 = 42.
To determine the total number of possible different outcomes when rolling one or two standard dice, we need to consider all the possible combinations.
When rolling one standard die, there are six possible outcomes since each die has six sides numbered 1 through 6.
When rolling two standard dice, we need to calculate the number of possible combinations. Each die can have six possible outcomes, and since there are two dice, we multiply the number of outcomes for each die together. This gives us 6 * 6 = 36 possible combinations.
Therefore, the total number of possible different outcomes when rolling either one or two standard dice is 6 + 36 = 42.
To find the total number of possible different outcomes when rolling one or two standard dice, we need to consider the different combinations that can occur.
When rolling one standard die, there are six possible outcomes: 1, 2, 3, 4, 5, and 6.
When rolling two standard dice, we can calculate the total number of outcomes by multiplying the number of outcomes from each die. Since each die has six sides, the total number of outcomes when rolling two dice is 6 * 6 = 36.
However, we need to consider that when rolling two dice, some outcomes can yield the same sum. For example, rolling a 1 on the first die and a 3 on the second die results in the same sum (4) as rolling a 3 on the first die and a 1 on the second die.
To find the total number of distinct sums, we can create a sum table that lists all the possible outcomes when rolling two dice:
For the first die, the outcomes are: 1, 2, 3, 4, 5, 6.
For the second die, the outcomes are: 1, 2, 3, 4, 5, 6.
By adding the two outcomes together, we can calculate the sum:
1 + 1 = 2
1 + 2 = 3
1 + 3 = 4
...
6 + 5 = 11
6 + 6 = 12
From the sum table, we can see that there are 11 distinct sums: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.
Therefore, the total number of possible different outcomes when rolling one or two standard dice is 6 (for rolling one die) + 11 (for rolling two dice) = 17.