Solve the system of equations. 6x–5y=27 3x+5y=36 (1 point)
To solve the system of equations, we can add the two equations together to eliminate the y variable.
(6x - 5y) + (3x + 5y) = 27 + 36
Combining the terms and simplifying the right side:
9x = 63
Dividing both sides by 9:
x = 7
Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y.
6x - 5y = 27
(6 * 7) - 5y = 27
42 - 5y = 27
Subtracting 42 from both sides:
-5y = -15
Dividing both sides by -5:
y = 3
Therefore, the solution to the system of equations is x = 7 and y = 3.
To solve the system of equations:
Equation 1: 6x - 5y = 27
Equation 2: 3x + 5y = 36
One way to solve this system is by elimination method. Let's start by adding the two equations together:
(6x - 5y) + (3x + 5y) = 27 + 36
Simplifying:
9x = 63
Now, divide both sides of the equation by 9 to solve for x:
9x/9 = 63/9
x = 7
Now substitute the value of x back into one of the original equations (Equation 1) to solve for y:
6(7) - 5y = 27
Simplify:
42 - 5y = 27
Subtract 42 from both sides:
-5y = 27 - 42
-5y = -15
Divide both sides by -5 to solve for y:
y = -15 / -5
y = 3
Therefore, the solution to the system of equations is x = 7 and y = 3.
To solve the system of equations, you can use the method of elimination or substitution.
Let's use the method of elimination to solve this system. Start by adding the two equations together.
(6x - 5y) + (3x + 5y) = 27 + 36
Combine like terms:
6x - 5y + 3x + 5y = 63
Simplify:
9x = 63
Now, divide both sides of the equation by 9:
9x/9 = 63/9
x = 7
Now substitute this value back into one of the original equations. Let's use the first equation:
6x - 5y = 27
6(7) - 5y = 27
42 - 5y = 27
Subtract 42 from both sides:
-5y = 27 - 42
-5y = -15
Divide both sides by -5:
-5y/-5 = -15/-5
y = 3
So the solution to the system of equations is x = 7, y = 3.