Since the calculated P-value of 0.033908 (rows) and 0.038462 (columns) are less compared to the critical value of 0.05, and therefore the null hypothesis has to be accepted by rejecting the alternate hypothesis. That’s why, we conclude to say that the null hypothesis is not significant and the alternate hypothesis is considered as being statically significant because the mean for the amount of dirt removed by the two brand of laundry detergent and the water temperature at three different conditions (cold, warm & hot) are not equal, they ranges from 22-36 and 11, 21 & 26 respectively, which are all different. On the other hand, for the F-value, both calculated F-value of 28 (rows) and 25 (columns) is greater than the f-critical value of 18.512821 and 19 respectively. Therefore, we say that the alternate hypothesis will be accepted and the null hypothesis will be rejected.
paraphrase it
Since the P-values for both the rows and the columns (0.033908 and 0.038462, respectively) are lower than the critical value of 0.05, we can conclude that the null hypothesis should be accepted, and the alternative hypothesis should be rejected. Therefore, the null hypothesis is not significant, and the alternative hypothesis is considered to be statistically significant, as the mean values for the amount of dirt removed by the two brands of laundry detergent and the water temperature at three different conditions (cold, warm, and hot) are not equal. These mean values range from 22-36 for the amount of dirt removed and 11, 21, and 26 for the different water temperatures, which are all different. Additionally, both the calculated F-values (28 for rows and 25 for columns) are greater than the critical F-value of 18.512821 and 19, respectively. Therefore, we can conclude that the alternate hypothesis will be accepted, and the null hypothesis will be rejected.
The P-values calculated for both the rows and columns (0.033908 and 0.038462, respectively) are smaller than the significance level of 0.05. This leads us to reject the null hypothesis and accept the alternative hypothesis, indicating that the mean amount of dirt removed by the two different laundry detergent brands and the water temperature at different conditions (cold, warm, and hot) are not equal. The values range from 22 to 36 for the detergent brands and 11, 21, and 26 for the water temperatures, all of which are different. Additionally, the calculated F-values of 28 for the rows and 25 for the columns are greater than the critical F-values of 18.512821 and 19, respectively. Therefore, we can conclude that the alternative hypothesis is significant and the null hypothesis is not significant.
Based on the calculated P-values (0.033908 for rows and 0.038462 for columns) being less than the critical value of 0.05, we can accept the null hypothesis by rejecting the alternate hypothesis. This means that the null hypothesis is not significant, and the alternate hypothesis is statistically significant. The mean for the amount of dirt removed by the two brands of laundry detergent and the water temperature at three different conditions (cold, warm, and hot) are not equal, with ranges from 22-36 and 11, 21, and 26 respectively.
In relation to the F-value, both the calculated F-value of 28 for rows and 25 for columns are greater than the f-critical values of 18.512821 and 19 respectively. Therefore, we can conclude that the alternate hypothesis is accepted and the null hypothesis is rejected.